this post was submitted on 26 Dec 2024
220 points (98.2% liked)

Asklemmy

44173 readers
2359 users here now

A loosely moderated place to ask open-ended questions

Search asklemmy ๐Ÿ”

If your post meets the following criteria, it's welcome here!

  1. Open-ended question
  2. Not offensive: at this point, we do not have the bandwidth to moderate overtly political discussions. Assume best intent and be excellent to each other.
  3. Not regarding using or support for Lemmy: context, see the list of support communities and tools for finding communities below
  4. Not ad nauseam inducing: please make sure it is a question that would be new to most members
  5. An actual topic of discussion

Looking for support?

Looking for a community?

~Icon~ ~by~ ~@Double_A@discuss.tchncs.de~

founded 5 years ago
MODERATORS
 

How about ANY FINITE SEQUENCE AT ALL?

you are viewing a single comment's thread
view the rest of the comments
[โ€“] Lanthanae@lemmy.blahaj.zone 5 points 20 hours ago (3 children)

Its not stupid. To disprove a claim that states "All X have Y" then you only need ONE example. So, as pick a really obvious example.

[โ€“] Umbrias@beehaw.org 2 points 13 hours ago (2 children)

it's not a good example because you've only changed the symbolic representation and not the numerical value. the op's question is identical when you convert to binary. thir is not a counterexample and does not prove anything.

[โ€“] Lanthanae@lemmy.blahaj.zone 1 points 8 hours ago (1 children)

They didn't convert anything to anything, and the 1.010010001... number isn't binary

[โ€“] Umbrias@beehaw.org 1 points 6 hours ago (1 children)

then it's not relevant to the question as it is not pi.

[โ€“] spireghost@lemmy.zip 1 points 3 hours ago* (last edited 3 hours ago)

The question is

Since pi is infinite and non-repeating, would it mean...

Then the answer is mathematically, no. If X is infinite and non-repeating it doesn't.

If a number is normal, infinite, and non-repeating, then yes.

To answer the real question "Does any finite sequence of non-repeating numbers appear somewhere in Pi?"

The answer depends on if Pi is normal or not, but not necessarily

[โ€“] orcrist@lemm.ee 1 points 9 hours ago (1 children)

Please read it all again. They didn't rely on the conversion. It's just a convenient way to create a counterexample.

Anyway, here's a simple equivalent. Let's consider a number like pi except that wherever pi has a 9, this new number has a 1. This new number is infinite and doesn't repeat. So it also answers the original question.

[โ€“] Umbrias@beehaw.org 2 points 6 hours ago (1 children)

"please consider a number that isnt pi" so not relevant, gotcha. it does not answer the original question, this new number is not normal, sure, but that has no bearing on if pi is normal.

[โ€“] spireghost@lemmy.zip 1 points 3 hours ago* (last edited 3 hours ago) (1 children)

OK, fine. Imagine that in pi after the quadrillionth digit, all 1s are replaced with 9. It still holds

[โ€“] Umbrias@beehaw.org 1 points 55 minutes ago

"ok fine consider a number that still isn't pi, it still holds." ??