A good example is https://lemmy.world/c/documentaries
One of their mods, https://lemmy.world/u/sabbah, currently mods 54 communites despite only being on Lemmy for about a month and has never posted on c/documentaries (except for his post asking for people to join his mod team).
The other mod, https://lemmy.world/u/AradFort, has one post to c/documentaries and moderates 18 communities.
Does Lemmy.World have a plan to remove this kind of cancer before we start getting reddit supermods here too?
Edit: This comment shows how this is even more dangerous than I had thought.
Edit2: Official answer from LW admin is here
@antik@lemmy.world
Tagging you in this thread too. Sorry if this isn't the most effective/preferred method
If you're interested in one of those communities and the mod is still active - pick it up with them first. In cases where the mods have abandoned the community completely we as admins can transfer the community to a new mod/team.
Edit: https://lemmy.world/post/1661949
Good to know, thank you! Was just interested in LW's official stance.
Thank you for the response! I had begun to wonder about this too, since I've seen a few examples of it in passing.
That question keeps coming up as if users can not create multiple accounts to circumvent that. As I said as long as they manage to get teams together and actively moderate those communities following the community guidelines and server rules there's not much that can be done. And this is NOT reddit 2.0 - there are other instances were the exact same communities can be created and grow.
If we are taking that approach, does that not make the rest of the rules unenforceable as well?
How would you even know that it is the same person if they use two separate accounts?
Say someone does something against the rules, gets banned. Creates another account and does the same thing. We will ban them again if they violate the server rules but how would we know that it was the same person?
Unless it's an obvious troll posting the same stuff over and over on different accounts.
I'm sorry but your logic makes no sense.
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