Asklemmy

43917 readers

1548 users here now

A loosely moderated place to ask open-ended questions

Search asklemmy 🔍

If your post meets the following criteria, it's welcome here!

Open-ended question
Not offensive: at this point, we do not have the bandwidth to moderate overtly political discussions. Assume best intent and be excellent to each other.
Not regarding using or support for Lemmy: context, see the list of support communities and tools for finding communities below
Not ad nauseam inducing: please make sure it is a question that would be new to most members
An actual topic of discussion

Looking for support?

Looking for a community?

Lemmyverse: community search
sub.rehab: maps old subreddits to fediverse options, marks official as such
!lemmy411@lemmy.ca: a community for finding communities

~Icon~ ~by~ ~@Double_A@discuss.tchncs.de~

founded 5 years ago

MODERATORS

Finding an instance that blocks least and is least blocked (lemmy.one)

submitted 1 year ago by Kurt@lemmy.one to c/asklemmy@lemmy.ml

102 comments fedilink hide all child comments

Is there a way to shop around for a Lemmy instance based on how many instances are blocking it and how many instances it's blocking? For example, I noticed that the lemmygrad.ml instance is relatively popular, but it seems like a lot of other instances block it. It also blocks a bunch of other instances. So, if there are any communities on there that might be relevant to me then I would be missing out. I guess I could just create an account on a walled instance, but I would prefer not to keep creating accounts. I'd like to just find one instance that maximizes my access. Is the answer to just run my own instance?

you are viewing a single comment's thread
view the rest of the comments

[–] RedMarsRepublic@lemmy.world 1 points 1 year ago

What a ridiculous false dichotomy, obviously subs which are just creating outright machine spam should be blocked but the current policy is just creating complete echo chambers where the orthodoxy of the admins isn't challenged.