Yeah, you would only need to burn a little bit more on your initial burn, that's why I said the cost would be similar.
Bumblefumble
It's definitely harder to decay the orbit into the sun directly than it is to get to escape velocity. But to play devil's advocate, there is probably a way to get them into the sun while being a similar cost to escape velocity. All you need to do is burn prograde to a super high aphelion, ride all the way out there to Pluto or whatever and then do a small retrograde burn to bring your perihelion inside the sun's photosphere. When you then get back towards the sun years later you would slam into it with a sick velocity that I think would be worth the decades-long wait.
It's just not true though, unless you do an out then in maneuver.
No that's not really the case, the earth will be destroyed.
She's the person who managed to be so racist that MTG called her out publically for it, which is honestly quite impressive.
Technically there is no boundary, it's atmosphere all the way in. But what we might call the "surface" is the photosphere. That is where the density becomes "low" (read not insanely high) enough that light can escape in a free path.
The sun has an atmosphere so there are soundwaves coming out of it. It's actually all one big atmosphere getting thinner and thinner as you go out just like ours.
Well, 9.1% less money, but yes ;)
Sure, but there is a north say 30 ft away from the north pole.
Depends on where they met each other. If they for example fell in love during the main event of a trip to the north pole, that would change things a lot.
I'm more interested in wtf is a "Devin Nunes"?? Almost gives me cow vibes, but idk.
Yeah it probably is, my comment was really about raw deltaV numbers without using gravity assists.