And we're already posting screenshots of reddit posts that are screenshots of tiktoks. Awesome
this post was submitted on 21 Jun 2023
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For x in range(∞):
If x % 2 == 0:
Print('Even')
Else:
Print('Opposite of even')
how....odd
😎
This media brings upon me a great factor of displeasure
This is literally how I code stuff when I'm sleepy, then I come back a month later and realize how horrible the code was. Pretty sure I can still find stuff like this in my old discontinued projects that I haven't cleaned up
I can't even.
Well that's odd :p
Just imagine he excel pulls that shit to infinity
I feel like I accidentally do something similar everytime I program anything. I am just bad at it, I don't know the short cuts or all the commands, but by God, it will work when I am done with it... maybe.
I don't know the right wat to do this, but I think there would be something like:
x = Number
If (x//2)is.integer() == "true":
Print("Even")
Else:
Print("odd")
Maybe? Idk. Probably a bunch of syntax issues and I haven't written anything in like a year.
You basically got it yeah. You can do x % 2 and check if that is 0, as % calculates the remainder (in python at least)
y = 1
while y ==1:
x = input("Enter Number")
if int(x) % 2 == 0:
print("EVEN")
else:
print("ODD")
I don't know why, but I opened up my IDLE for the first time in a year and did it.
int val = 3;
bool is_odd = val & (decltype(val))0x01 == (decltype (val))1;
Know you probably don’t care, but you can do a while loop using while True:
Which is the same as you using a statement which equals to true.
Thought i don’t think you need it for what you’re doing currently.
Unless you want it to keep asking the question of course**
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