rudt has implicit typing by default for variables tho...?
this post was submitted on 14 Nov 2023
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Yeah but it doesn't cross function boundaries so it's more limited.
In other words, in OCaml, you don't have to write type annotations into the function parameter list. It will infer even those.
It's useful for small ad-hoc functions, but personally, I'm glad that Rust is more explicit here.
yeah structs, consts ets should always be explicit, prevents a lot oh headache
also, for adhoc stuff rust has closures which can be fully inferred (but you need to convert them to explicit function pointers for storage in structs/consts)
It's not like it's more limited, it's just so that it can yell at you when you return not what you said you're going to, IMO
OCaml allows you to specify return types, but doesn't force you to.
Why am I laughing? I don't know any of these languages?
Feel like this joke would work better with TS | JS. Since that's the point of the former. I don't know how rust and ocaml are related?
The initial creator of Rust, Graydon Hoare, took lots of inspiration from OCaml. In fact, the first Rust compiler was written in OCaml.
I appreciate that fun fact. The meme now makes more sense.
JS doesn't do any type inference. Ocaml Connor l type checker knows all the types and is completely type safe without type annotations.
OCaml stronk... it's an amazing language that more people should be familiar with!