this post was submitted on 19 Sep 2024
12 points (73.1% liked)

Ask Science

8596 readers
24 users here now

Ask a science question, get a science answer.


Community Rules


Rule 1: Be respectful and inclusive.Treat others with respect, and maintain a positive atmosphere.


Rule 2: No harassment, hate speech, bigotry, or trolling.Avoid any form of harassment, hate speech, bigotry, or offensive behavior.


Rule 3: Engage in constructive discussions.Contribute to meaningful and constructive discussions that enhance scientific understanding.


Rule 4: No AI-generated answers.Strictly prohibit the use of AI-generated answers. Providing answers generated by AI systems is not allowed and may result in a ban.


Rule 5: Follow guidelines and moderators' instructions.Adhere to community guidelines and comply with instructions given by moderators.


Rule 6: Use appropriate language and tone.Communicate using suitable language and maintain a professional and respectful tone.


Rule 7: Report violations.Report any violations of the community rules to the moderators for appropriate action.


Rule 8: Foster a continuous learning environment.Encourage a continuous learning environment where members can share knowledge and engage in scientific discussions.


Rule 9: Source required for answers.Provide credible sources for answers. Failure to include a source may result in the removal of the answer to ensure information reliability.


By adhering to these rules, we create a welcoming and informative environment where science-related questions receive accurate and credible answers. Thank you for your cooperation in making the Ask Science community a valuable resource for scientific knowledge.

We retain the discretion to modify the rules as we deem necessary.


founded 1 year ago
MODERATORS
you are viewing a single comment's thread
view the rest of the comments
[–] Muun@lemmy.world 12 points 1 month ago* (last edited 1 month ago) (2 children)

Okay, very confusing question...

So, assuming you want to know how heavy only the "solid at room temperature" elements of the sun are, let's try this.

The sun is 1.989 × 10^30 kilograms.

According to this: https://www.thoughtco.com/element-composition-of-sun-607581 we can see the % of total mass for each element.

  • Element % of total atoms % of total mass
  • Hydrogen 91.2 71.0
  • Helium 8.7 27.1
  • Oxygen 0.078 0.97
  • Carbon 0.043 0.40
  • Nitrogen 0.0088 0.096
  • Silicon 0.0045 0.099
  • Magnesium 0.0038 0.076
  • Neon 0.0035 0.058
  • Iron 0.030 0.014
  • Sulfur 0.015 0.040

Doing the math and removing the "gas at room temperature" elements... the total mass would be:

1.7901 * 10^28 kilograms

Note: Pretty sure I've messed something up here in the calculations but the mass is so ridiculously heavy that I don't think it really matters.

[–] Admetus@sopuli.xyz 4 points 1 month ago* (last edited 1 month ago)

Seems like you answered the question, OP comments at the bottom and thinks it might be picked up by hand in terms of weight.

[–] kbal@fedia.io 0 points 1 month ago

Not many rocks don't have some oxygen atoms in them, so I chose to include all the astronomical "metals" in my estimate. Interesting to see how little difference it makes.