this post was submitted on 09 Sep 2024
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    [–] crimsoncobalt@lemmy.world 17 points 2 months ago (15 children)

    Does this really work? Wouldn't rm remove itself in /bin early in the process?

    [–] rbn@sopuli.xyz 49 points 2 months ago* (last edited 2 months ago) (5 children)

    I think it would continue even after it's own deletion as the binary is already loaded into memory, so process is not dependent on the file system. Still doubt that it'll complete successfully. Most likely the system crashes in the middle.

    [–] kirk781@discuss.tchncs.de 13 points 2 months ago (1 children)

    I thought - - no-preserve root also needed to be added as an argument for self destruct to completely work.

    [–] elvith@feddit.org 12 points 2 months ago* (last edited 2 months ago) (1 children)

    Yes, though you could also do rm -rf /* afaik to not need --no-preserve-root

    Edit: I just realized that the * is already in the meme. So this should already work as is. Alternatively you could always use the good old way of "act now and remove all French roots of your system: rm -fr / --no-preserve-root"

    [–] blibla@slrpnk.net 1 points 2 months ago (1 children)

    i dont get why you can't just do sudo rm -fr /

    [–] elvith@feddit.org 3 points 2 months ago

    because it won't let you do that:

    elvith@testvm:~$ sudo rm -fr /

    rm: it is dangerous to operate recursively on '/'

    rm: use --no-preserve-root to override this failsafe

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