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got him (lemy.lol)

submitted 6 months ago by ngn@lemy.lol to c/programmerhumor@lemmy.ml

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[–] Tyoda@lemm.ee 0 points 6 months ago* (last edited 6 months ago) (2 children)

Perhaps *(p += 1) will be to your liking?

[–] fluckx@lemmy.world 0 points 6 months ago* (last edited 6 months ago) (1 children)

p = 1

x = ++p
// x = 2
// p = 2

p = 1
x  = p++
// x = 1
// p = 2

++p will increase the value and return the new value

p++ will increase the value and return the old value

I think p = p + 1 is the same as p++ and not as ++p. No?

[–] SpaceNoodle@lemmy.world 0 points 6 months ago* (last edited 6 months ago) (1 children)

(p += 1) resolves to the value of p after the incrementation, as does ( p = p + 1).

[–] fluckx@lemmy.world 0 points 6 months ago (1 children)

Yes.

p++ == p+= 1 == p = p + 1 are all the same if you use it in an assignment.

++p is different if you use it in an assignment. If it's in its own line it won't make much difference.

That's the point I was trying to make.

[–] SpaceNoodle@lemmy.world 1 points 6 months ago

No.

++p returns incremented p.

p += 1 returns incremented p.

p = p + 1 returns incremented p.

p++ returns p before it is incremented.

[–] xmunk@sh.itjust.works -1 points 6 months ago (1 children)

Much better... but can we make it *((void*)(p = p + 1))?

[–] shrugal@lemm.ee -1 points 6 months ago

How about some JavaScript p+=[]**[]?