this post was submitted on 11 Oct 2023
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Brilliant, now I wonder what ages this works for, I figured only 1 and 2, but then I realised we could write the father's age in other bases..
1 = 2^0 (20 b10)
2 = 2^1 (21 b10)
3 = 3^1 (31 b7 = 22)
6 = 6^1 (61 b4 = 25) if they are lucky the grand father will be 61 that year :-D
8 = 2^3 (23 b12 =27)
9 = 9^1 (91 b3 = 28)
14 = 14^1 (141 b4 = 33)
You have mistakes in a few of those. The number "61" doesnt exist in b4. 25b10 in b4 is "121".
Similar problem with 91b3 and 141b4.
Indeed, I was so focused on the algebraic side I didn't even think about it :-D
I was computing 6*4+1=25