this post was submitted on 26 Aug 2023
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    Which way do you expand variables? (lemmy.world)
    submitted 1 year ago by zephyr@lemmy.world to c/linuxmemes@lemmy.world
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    [–] Synthead@lemmy.world 4 points 1 year ago (2 children)

    If the strings don't contain characters that help define a variable, like an underscore, how is it better practice to use curlies? It's it just for consistency? Have you had any style guides or linters critique the use of variables without them?

    [–] SpaceNoodle@lemmy.world 21 points 1 year ago* (last edited 1 year ago)

    More than anything, I find that it's a good habit to maintain in order to avoid simple mistakes. It also makes variables easier to spot in code and maintains consistency.

    [–] RazorsLedge@lemmy.world 17 points 1 year ago* (last edited 1 year ago) (1 children) 
    foo=ding
foobar=dong

echo \$foobar

    Brackets make it explicit what you're trying to do. Do you want "dingbar" or do you want "dong"? I forget what the actual behavior is if you don't use brackets here, because I always use brackets for this reason now

    [–] subtext@lemmy.world 4 points 1 year ago (1 children)

    I believe the actual behavior here would be printing “dong” as the shell interpreter is greedy in its evaluation of variables.

    [–] vrighter@discuss.tchncs.de 2 points 1 year ago

    the actual behavior here is to echo the literal string "$foobar", because the $ sign is escaped. so no variable expansion will take place at all.