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submitted 1 year ago by The_Picard_Maneuver@lemmy.world to c/memes@lemmy.ml

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[–] blanketswithsmallpox@kbin.social 29 points 1 year ago* (last edited 1 year ago) (3 children)

I'm a little sad nobody has done the correct math and it's been too long for me to do it off the top of my head lol.

A^2+B^2=C^2? What distance are the diagonals if the sides are 6' apart?

6x6 + 6x6 = sqrt72 = 8.49' !

I did it bois. Ty calculator for sqrt72...

[–] Kongpiler@lemm.ee 21 points 1 year ago (1 children)

Now do the conversion factor from feef to feet!

[–] TheFriendlyDickhead@lemm.ee 20 points 1 year ago

The diagonal is 6ft. The side is 6 ft. So 6² + 6feef² = 6²

1 feef = 0ft

[–] exu@feditown.com 4 points 1 year ago (2 children)

Now, what's the length of the sides if the diagonals are 6ft?

[–] TheFriendlyDickhead@lemm.ee 5 points 1 year ago* (last edited 1 year ago) (1 children)

Thats easy.
6 * 6 = 36
36 = a² + b²
Lets assume a = b
So a² = 18 = b²
a = b = 4,2426406871

[–] shootwhatsmyname@lemm.ee 1 points 1 year ago

What if every initial value is unknown?

[–] MrMamiya@feddit.de 2 points 1 year ago

Roughly 4.24?

[–] Unanimous_anonymous@lemmy.ml 2 points 1 year ago

8.49'!~=116699.97'

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