this post was submitted on 05 Aug 2023

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Java (lemmy.world)

submitted 1 year ago by alphacyberranger@lemmy.world to c/programmer_humor@programming.dev

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[–] RoyaltyInTraining@lemmy.world 2 points 1 year ago

A double can represent numbers up to +- 1.79769313486231570x10^308, or roughly 18 with 307 zeroes behind it. You can't fit that into a long, or even 128 bits. Even though rounding huge doubles is pointless, since only the first dozen digits or so are saved, using any kind of Integer would lead to inconsistencies, and thus potentially bugs.