this post was submitted on 17 Jul 2024
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Showerthoughts

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Amazon is running a Prime Day sale on July 16 and 17. Setting aside the fact that this is two separate days, neither 716 nor 717 are prime numbers. They should've done 7/19 instead.

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[–] EmoDuck@sh.itjust.works 13 points 4 months ago (9 children)

How the hell is 717 not a prime number? Who fucked that up? I vote we just change that

[–] olafurp@lemmy.world 3 points 4 months ago (8 children)

Divisible by 3. Easy to check since 7 + 1 + 7 = 15 which is divisible by 3.

[–] FeatherConstrictor@sh.itjust.works 4 points 4 months ago (7 children)

Oh awesome that's a neat trick I've never seen before. How does that work? For a number like 700 for example, 7 + 0 + 0 = 7 but 700 is visible by 10.

[–] Wasgaytsiedasan@feddit.de 5 points 4 months ago (1 children)

You can only use this method to check if the number can be divided by 3.

[–] booly@sh.itjust.works 2 points 4 months ago (1 children)
[–] booly@sh.itjust.works 2 points 4 months ago

If you're looking for a proof:

Our base 10 system represents numbers by having little multipliers in front of each power of 10. So a number like 1234 is 1 x 10^3 + 2 x 10^2 + 3 x 10^1 + 4 x 10^0 .

Note that 10 is just (3 x 3) + 1. So for any 2 digit number, you're looking at the first digit times (9 + 1), plus the second digit. Or:

(9 times the first digit) + (the first digit) + (the second digit).

Well we know that 9 times the first digit is definitely divisible by both 3 and 9. And we know that adding two divisible-by-n numbers is also divisible by n.

So we can ignore that first term (9 x first digit), and just look to whether first digit plus second digit is divisible. If it is, then you know that the original big number is divisible.

And when you extend this concept out to 3, 4, or more digit numbers, you see that it holds for every power of 10, and thus, every possible length of number. For both 9 and 3.

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